32(4x+5)=4^4x

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Solution for 32(4x+5)=4^4x equation: 



32(4x+5)=4^4x

We move all terms to the left:

32(4x+5)-(4^4x)=0

We multiply parentheses

128x-4^4x+160=0

We move all terms containing x to the left, all other terms to the right

128x-4^4x=-160

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